The initial value theorem lets you read off a signal’s value at directly from its Laplace transform, without inverting:

provided has no impulses at .

Why it works

For a unilateral transform , as the kernel concentrates more and more sharply at , so the integral approaches the initial value of . The factor of scales the kernel back to integral in the limit.

A non-rigorous but quick derivation: by the unilateral differentiation property, . Take on both sides. The left side goes to zero (the kernel vanishes for any fixed , leaving only a small contribution near from the jump ). The right side becomes . Equating: .

Worked example

The IVT requires to be strictly proper (numerator degree strictly less than denominator degree). If you try it on something improper like — same degrees — you get

which diverges. That’s the signature that contains an impulse at and the IVT doesn’t apply.

For a proper like :

So . Check: gives . ✓

When it’s useful

You’re given as a rational function and want the initial value of without bothering to invert. Common in checking solutions to ODE initial-value problems, or in characterizing step responses without computing the full time-domain function.

Conditions

  • must have no impulse at (so must be a proper rational function).
  • Either exists, or converges in some right half-plane.

For most engineering problems the conditions hold, and the IVT is a fast sanity check.

See also

The companion result for the long-time behavior is the Final value theorem, which gives — useful for finding the steady-state value of a system’s response.